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Unformatted text preview: C 2 ) we have an equivalent capacitance of C = 8 . F which has charge q = q 2 and potential dierence equal to that of C 1 . Thus, V 1 = V q 1 C 1 = q 2 C which yields 4 q 1 = q 2 . Therefore, Q = q 1 + 4 q 1 leads to q 1 = 8 . C and consequently to q 2 = 32 C. (b) From Eq. 261, we have V 2 = (32 C)(16 F) = 2 . 0 V....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics, Charge, Energy, Heat

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