P26_052 - C 2 ) we have an equivalent capacitance of C = 8...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
52. (a) We do not employ energy conservation since, in reaching equilibrium, some energy is dissipated either as heat or radio waves. Charge is conserved; therefore, if Q = C 1 V bat = 40 µ C, and q 1 and q 2 are the charges on C 1 and C 2 after the switch is thrown to the right and equilibrium is reached, then Q = q 1 + q 2 . Reducing the right portion of the circuit (the C 3 , C 4 parallel pair which are in series with
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: C 2 ) we have an equivalent capacitance of C = 8 . F which has charge q = q 2 and potential dierence equal to that of C 1 . Thus, V 1 = V q 1 C 1 = q 2 C which yields 4 q 1 = q 2 . Therefore, Q = q 1 + 4 q 1 leads to q 1 = 8 . C and consequently to q 2 = 32 C. (b) From Eq. 26-1, we have V 2 = (32 C)(16 F) = 2 . 0 V....
View Full Document

This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

Ask a homework question - tutors are online