P26_052

# P26_052 - C 2 ) we have an equivalent capacitance of C = 8...

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52. (a) We do not employ energy conservation since, in reaching equilibrium, some energy is dissipated either as heat or radio waves. Charge is conserved; therefore, if Q = C 1 V bat = 40 µ C, and q 1 and q 2 are the charges on C 1 and C 2 after the switch is thrown to the right and equilibrium is reached, then Q = q 1 + q 2 . Reducing the right portion of the circuit (the C 3 , C 4 parallel pair which are in series with
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Unformatted text preview: C 2 ) we have an equivalent capacitance of C = 8 . F which has charge q = q 2 and potential dierence equal to that of C 1 . Thus, V 1 = V q 1 C 1 = q 2 C which yields 4 q 1 = q 2 . Therefore, Q = q 1 + 4 q 1 leads to q 1 = 8 . C and consequently to q 2 = 32 C. (b) From Eq. 26-1, we have V 2 = (32 C)(16 F) = 2 . 0 V....
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## This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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