P26_053 - 53. Using Eq. 26-27, with = q/A, we have E= q =...

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53. Using Eq. 26-27, with σ = q/A ,wehave ¯ ¯ ¯ ~ E ¯ ¯ ¯ = q κε 0 A = 200 × 10 3 N / C which yields q =3 . 3 × 10 7 C. Eq. 26-21 and Eq. 26-25 therefore lead to
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