P26_055 - 55(a We use q = CV = 0 AV/d to solve for A A= Cd(10 1012 F(1.0 103 m = = 1.1 103 m2 2 0 8.85 1012 NC 2 m(b Now C =C d d =(10 pF 1.0 mm

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55. (a) We use q = CV = ε 0 AV/d to solve for A : A = Cd ε 0 = (10 × 10 12 F)(1 . 0 × 10 3 m) ( 8 . 85 × 10 12 C 2 N · m 2 ) =1 . 1 × 10 3 m 2 . (b) Now, C 0 = C µ d d 0 =(10pF) µ 1 . 0mm 0 . 9mm =11pF . (c) The new potential di±erence is V 0 = q/C 0 = CV/C 0 .Thu s , V = V 0 V = (10 pF)(12 V) 11 pF 12 V = 1 . 2V
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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