P26_056 - C and 2 C capacitors are now in series...

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56. (a) Here D is not attached to anything, so that the 6 C and 4 C capacitors are in series (equivalent to 2 . 4 C ). This is then in parallel with the 2 C capacitor, which produces an equivalence of 4 . 4 C . Finally the 4 . 4 C is in series with C and we obtain C eq = ( C )(4 . 4 C ) C +4 . 4 C =0 . 82 C =41 µ F wherewehaveusedthefactthat C =50 µ F. (b) Now, B is the point which is not attached to anything, so that the 6
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Unformatted text preview: C and 2 C capacitors are now in series (equivalent to 1 . 5 C ), which is then in parallel with the 4 C capacitor (and thus equivalent to 5 . 5 C ). The 5 . 5 C is then in series with the C capacitor; consequently, C eq = ( C ) (5 . 5 C ) C + 5 . 5 C = 0 . 85 C = 42 F ....
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