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Unformatted text preview: 57. In the ﬁrst case the two capacitors are eﬀectively connected in series, so the output potential diﬀerence
is Vout = CVin /2C = Vin /2 = 50.0 V. In the second case the lower diode acts as a wire so Vout = 0. ...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
- Fall '08