P26_067 - . 9 10 4 C , q 2 = 2 q q 1 = 7 . 7 10 4 C , V = q...

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67. (a) The equivalent capacitance is C eq = C 1 C 2 / ( C 1 + C 2 ) . Thus the charge q on each capacitor is q = C eq V = C 1 C 2 V C 1 + C 2 = (2 . 0 µ F)(8 . 0 µ F)(300 V) 2 . 0 µ F+8 . 0 µ F =4 . 8 × 10 4 C . The potential diferences are: V 1 = q/C 1 =4 . 8 × 10 4 C / 2 . 0 µ F = 240 V, V 2 = V V 1 = 300 V 240 V = 60 V . (b) Now we have q 0 1 /C 1 = q 0 2 /C 2 = V 0 ( V 0 being the new potential diference across each capacitor) and q 0 1 + q 0 2 =2 q .W eso lv e±o r q 0 1 , q 0 2 and V : q 0 1 = 2 C 1 q C 1 + C 2 = 2(2 . 0 µ F)(4 . 8 × 10 4 C) 2 . 0 µ F+8 .
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Unformatted text preview: . 9 10 4 C , q 2 = 2 q q 1 = 7 . 7 10 4 C , V = q 1 C 1 = 1 . 92 10 4 C 2 . F = 96 V . (c) In this circumstance, the capacitors will simply discharge themselves, leaving q 1 = q 2 = 0 and V 1 = V 2 = 0....
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