P26_068 - 2 Thus(1 ∆ V/V 2 = 1 ∆ U/U or ∆ V V = r 1 ∆ U U − 1 = p 1 10 − 1 = 4 9.

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68. We use U = 1 2 CV 2 .A s V is increased by ∆ V , the energy stored in the capacitor increases correspondingly from U to U +∆ U : U +∆ U = 1 2 C ( V +∆
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Unformatted text preview: ) 2 . Thus, (1 + ∆ V/V ) 2 = 1 + ∆ U/U , or ∆ V V = r 1 + ∆ U U − 1 = p 1 + 10% − 1 = 4 . 9% ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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