69. (a) The voltage across C 1 is 12 V, so the charge is q 1 = C 1 V 1 =24 µ C . (b) We reduce the circuit, starting with C 4 and C 3 (in parallel) which are equivalent to 4 µ F. This is then in series with C 2 , resulting in an equivalence equal to 4 3 µ F which would have 12 V across it. The charge on this
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