P26_074 - 74. (a) The length d is effectively shortened by...

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Unformatted text preview: 74. (a) The length d is effectively shortened by b so C = ε0 A/(d − b). (b) The energy before, divided by the energy after inserting the slab is q 2 /2C C U ε0 A/(d − b) d =2 = = = . U q /2C C ε0 A/d d−b (c) The work done is W = ∆U = U − U = Since W < 0 the slab is sucked in. q2 2 1 1 − C C = q2 q2b (d − b − d) = − . 2 ε0 A 2 ε0 A ...
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