This preview shows page 1. Sign up to view the full content.
Unformatted text preview: . We reduce the series pair C 2 and C 3 to C = 4 / 3 F which has charge q = q 3 and the same voltage that we nd across C 1 . Therefore, V 1 = V q 1 C 1 = q 3 C which leads to q 1 = 1 . 5 q 3 . Hence, Q = (1 . 5 q 3 ) + q 3 leads to q 3 = 9 . 6 C....
View
Full
Document
This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics, Charge, Energy, Heat

Click to edit the document details