P26_081

# P26_081 - . We reduce the series pair C 2 and C 3 to C = 4...

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81. We do not employ energy conservation since, in reaching equilibrium, some energy is dissipated either as heat or radio waves. Charge is conserved; therefore, if Q = C 1 V bat =24 µ C, and q 1 and q 3 are the charges on C 1 and C 3 after the switch is thrown to the right (and equilibrium is reached), then Q = q 1 + q 3
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Unformatted text preview: . We reduce the series pair C 2 and C 3 to C = 4 / 3 F which has charge q = q 3 and the same voltage that we nd across C 1 . Therefore, V 1 = V q 1 C 1 = q 3 C which leads to q 1 = 1 . 5 q 3 . Hence, Q = (1 . 5 q 3 ) + q 3 leads to q 3 = 9 . 6 C....
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## This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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