P26_085 - q 1 /C 1 (see below) and (since the capacitors...

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85. (Fourth problem of Cluster ) (a) With the parallel pair C 2 and C 3 reduced to a single C 0 =45 µ F capacitor, this becomes very similar to problem 82. Using notation similar to that used in the solution to 82, we have Q = q 1 + q 0 where Q = C 1 V bat = 400 µ C. Also, after switch S is closed, V 1 = V 0 q 1 C 1 = q 0 C 0 which yields 9 8 q 1 = q 0 . Therefore, Q = q 1 + µ 9 8 q 1 which gives the result q 1 = 188 µ C. (b) We ±nd the voltage across capacitor 1 from
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Unformatted text preview: q 1 /C 1 (see below) and (since the capacitors are in parallel) use the fact that V 1 = V 2 = V 3 with q = CV to obtain the charges: q 2 = 71 µ C and q 3 = 141 µ C. (c) See part (b). (d) (e) and (f) The capacitors all have the same voltage. V = q 1 /C 1 = 4 . 7 V....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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