P27_003 - i out is the current leaving. Thus, t = q i in i...

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3. Suppose the charge on the sphere increases by ∆ q in time ∆ t . Then, in that time its potential increases by V = q 4 πε 0 r , where r is the radius of the sphere. This means q =4 πε 0 r V. Now, ∆ q =( i in i out )∆ t ,where i in is the current entering the sphere and
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Unformatted text preview: i out is the current leaving. Thus, t = q i in i out = 4 r V i in i out = (0 . 10 m)(1000 V) (8 . 99 10 9 F / m)(1 . 0000020 A 1 . 0000000 A) = 5 . 6 10 3 s ....
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