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6. We express the magnitude of the current density vector in SI units by converting the diameter values
in mils to inches (by dividing by 1000) and then converting to meters (by multiplying by 0
.
0254) and
Fnally using
J
=
i
A
=
i
πR
2
=
4
i
πD
2
.
±or example, the gauge 14 wire with
D
=64mil=0
.
0016 m is found to have a (maximum safe) current
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Unformatted text preview: density of J = 7 . 2 × 10 6 A/m 2 . In fact, this is the wire with the largest value of J allowed by the given data. The values of J in SI units are plotted below as a function of their diameters in mils. 4e+06 5e+06 6e+06 7e+06 J 40 60 80 100 120 140 160 180 200 D(mils)...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics, Current

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