P27_010 - resulting in a higher average current density...

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10. (a) The current resulting from this non-uniform current density is i = Z cylinder JdA = Z R 0 J 0 ³ 1 r R ´ 2 πrdr = 1 3 πR 2 J 0 = 1 3 AJ 0 . (b) In this case, i = Z cylinder JdA = J 0 R Z R 0 r · 2 πrdr = 2 3 πR 2 J 0 = 2 3 AJ 0 . The result is diFerent from that in part (a) because the current density in part (b) is lower near the center of the cylinder (where the area is smaller for the same radial interval) and higher outward,
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Unformatted text preview: resulting in a higher average current density over the cross section and consequently a greater current than that in part (a)....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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