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18. In Eq. 2717, we let
ρ
=2
ρ
0
where
ρ
0
is the resistivity at
T
0
=20
◦
C:
ρ
−
ρ
0
=2
ρ
0
−
ρ
0
=
ρ
0
α
(
T
−
T
0
)
,
and solve for the temperature
T
:
T
=
T
0
+
1
α
=20
◦
C+
1
4
.
3
×
10
−
3
/
K
≈
250
◦
C
.
Since a change in Celsius is equivalent to a change on the Kelvin temperature scale, the value of
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 Fall '08
 SPRUNGER
 Physics

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