P27_018 - 18. In Eq. 27-17, we let = 20 where 0 is the...

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18. In Eq. 27-17, we let ρ =2 ρ 0 where ρ 0 is the resistivity at T 0 =20 C: ρ ρ 0 =2 ρ 0 ρ 0 = ρ 0 α ( T T 0 ) , and solve for the temperature T : T = T 0 + 1 α =20 C+ 1 4 . 3 × 10 3 / K 250 C . Since a change in Celsius is equivalent to a change on the Kelvin temperature scale, the value of
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