P27_019 - and A = L A/L = L A 3 L = A 3 The new resistance...

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19. Since the mass and density of the material do not change, the volume remains the same. If L 0 is the original length, L is the new length, A 0 is the original cross-sectional area, and A is the new cross- sectional area, then L 0 A 0 = LA
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Unformatted text preview: and A = L A /L = L A / 3 L = A / 3. The new resistance is R = ρL A = ρ 3 L A / 3 = 9 ρL A = 9 R , where R is the original resistance. Thus, R = 9(6 . 0 Ω) = 54 Ω....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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