P27_028 - R = (1 . 00 )(25 ft / 1000 ft)(4) 2 = 0 . 40 .

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28. We use R L/A . The diameter of a 22-gauge wire is 1 / 4 that of a 10-gauge wire. Thus from R = ρL/A we Fnd the resistance of 25 ft of 22-gauge copper wire to be
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Unformatted text preview: R = (1 . 00 )(25 ft / 1000 ft)(4) 2 = 0 . 40 ....
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