Unformatted text preview: 37. (a) The power dissipated, the current in the heater, and the potential diﬀerence across the heater are related by P = iV . Therefore, 1250 W P = = 10.9 A . i= V 115 V (b) Ohm’s law states V = iR, where R is the resistance of the heater. Thus, R= 115 V V = = 10.6 Ω . i 10.9 A (c) The thermal energy E generated by the heater in time t = 1.0 h = 3600 s is E = P t = (1250 W)(3600 s) = 4.5 × 106 J . ...
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 Fall '08
 SPRUNGER
 Physics, Current, Resistance, Power, Heat

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