P27_037 - 37. (a) The power dissipated, the current in the...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 37. (a) The power dissipated, the current in the heater, and the potential difference across the heater are related by P = iV . Therefore, 1250 W P = = 10.9 A . i= V 115 V (b) Ohm’s law states V = iR, where R is the resistance of the heater. Thus, R= 115 V V = = 10.6 Ω . i 10.9 A (c) The thermal energy E generated by the heater in time t = 1.0 h = 3600 s is E = P t = (1250 W)(3600 s) = 4.5 × 106 J . ...
View Full Document

Ask a homework question - tutors are online