P27_038 - 38. (a) From P = V 2 /R = AV 2 /L, we solve for...

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38. (a) From P = V 2 /R = AV 2 /ρL , we solve for the length: L = AV 2 ρP = (2 . 60 × 10 6 m 2 )(75 . 0V) 2 (5 . 00 × 10 7 · m)(5000 W) =5 . 85 m . (b) Since L V 2 the new length should be
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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