P27_039 - is P H = V 2 /R H , so P L = ( R H /R L ) P H ....

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
39 .L e t R H be the resistance at the higher temperature (800 C) and let R L be the resistance at the lower temperature (200 C). Since the potential diference is the same For the two temperatures, the power dissipated at the lower temperature is P L = V 2
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: is P H = V 2 /R H , so P L = ( R H /R L ) P H . Now R L = R H + R H T , where T is the temperature diference T L T H = 600 C = 600 K. Thus, P L = R H R H + R H T P H = P H 1 + T = 500 W 1 + (4 . 10 4 / K)( 600 K) = 660 W ....
View Full Document

This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

Ask a homework question - tutors are online