Unformatted text preview: 45. (a) Since the area of a hemisphere is 2πr2 then the magnitude of the current density vector is
J= i
I
.
=
A
2πr2 (b) Eq. 2711 yields E = ρ J = ρI/2πr2 .
(c) Eq. 2518 leads to
r r E · dr = − ∆ V = Vr − V b = −
b (d) Using the given values, we obtain J = b
100
2π (10)2 ρI
2πr2 = 0.16 A/m2 . (e) Also, E = 16 V/m (or 16 N/C).
(f) With b = 0.010 m, the voltage is ∆V = −1.6 × 105 V. dr = ρI
2π 11
−
r
b . ...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics, Current

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