P27_064 - 64. A least squares fit of the data gives R =...

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Unformatted text preview: 64. A least squares fit of the data gives R = 537 5 + 1111 1750 T with T in degrees Celsius. (a) At T = 20◦ C, our expression gives R = (b) At T = 0◦ C, our expression gives R = 21017 175 ≈ 120 Ω. 537 5 ≈ 107 Ω. (c) Defining αR by αR = R − R20 R20 (T − 20◦ C) then we are effectively requiring αR R20 to equal the 1111 factor in our least squares fit. This implies 1750 that αR = 1111/210170 = 0.00529/C◦ if R20 = 21017 ≈ 120 Ω is used as the reference. 175 (d) Now we define αR by αR = R − R0 , R0 (T − 0◦ C) which means we require αR R0 to equal the 1111 factor in our least squares fit. In this case, 1750 αR = 1111/187950 = 0.00591/C◦ if R0 = 537 ≈ 107 Ω is used as the reference. 5 (e) Our least squares fit expression predicts R = 96473/350 ≈ 276 Ω at T = 265◦ C. ...
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