P27_067 - J A J B = i r 2 A i r 2 B = i r 2 A i 1 4 r 2 A =...

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67. (First problem of Cluster ) (a) We are told that r B = 1 2 r A and L B =2 L A . Thus, using Eq. 27-16, R B = ρ L B πr 2 B = ρ 2 L A 1 4 πr 2 A =8 R A =64Ω . (b) The current-densities are assumed uniform.
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Unformatted text preview: J A J B = i r 2 A i r 2 B = i r 2 A i 1 4 r 2 A = 1 4 ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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