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69. (Third problem of
Cluster
)
(a) We use Eq. 2717 with
ρ
=
10
8
ρ
0
(we are neglecting any thermal expansion of the material) and
T
−
T
0
= 100 K in order to obtain
α
=2
.
5
×
10
−
3
/
K. Now with this value of
α
but
T
= 600 K (so
T
−
T
0
= 300 K) we Fnd
ρ
=1
.
75
ρ
0
→
R
=1
.
75(8
.
0Ω)=14Ω.
(b) We are assuming the wires have unknown but equal length (not the lengths shown in ±igure 2733).
With
α
D
=5
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics

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