P27_070 - = 7 . 2 = 1 + ( T 300) . Using Table 27-1 ( = 4 ....

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70. (Fourth problem of Cluster ) From Eq. 27-23, we obtain the resistance at temperature T : R = V 2 P = 12 2 10 =14 . 4Ω . Thus, the ratio R/R 0 with R 0 representing the resistance at 300 K is 7 . 2, which we take to equal the ratio of resistivities (ignoring any thermal expansion of the ±lament). Eq. 27-17, then, leads to
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Unformatted text preview: = 7 . 2 = 1 + ( T 300) . Using Table 27-1 ( = 4 . 5 10 3 / K) we nd T = 1 . 7 10 3 K....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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