P28_017 - R = r . (b) When R = r , the power dissipated in...

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17. (a) Using Eq. 28-4, we take the derivative of the power P = i 2 R with respect to R and set the result equal to zero: dP dR = d dR µ E 2 R ( R + r ) 2 = E 2 ( r R ) ( R + r ) 3 =0 which clearly has the solution
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Unformatted text preview: R = r . (b) When R = r , the power dissipated in the external resistor equals P max = E 2 R ( R + r ) 2 ¯ ¯ ¯ ¯ R = r = E 2 4 r ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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