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21. Let
i
1
be the current in
R
1
and take it to be positive if it is to the right. Let
i
2
be the current in
R
2
and take it to be positive if it is upward. When the loop rule is applied to the lower loop, the result is
E
2
−
i
1
R
1
=0
.
and when it is applied to the upper loop, the result is
E
1
−E
2
−E
3
−
i
2
R
2
=0
.
The Frst equation yields
i
1
=
E
2
R
1
=
5
.
0V
100 Ω
=0
.
050 A
.
The second yields
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics, Current

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