P28_023 - (b) When the bulbs are connected in series the...

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23. (a) Let E be the emf of the battery. When the bulbs are connected in parallel, the potential diFerence across them is the same and is also the same as the emf of the battery. The power dissipated by bulb 1 is P 1 = E 2 /R 1 , and the power dissipated by bulb 2 is P 2 = E 2 /R 2 .S ince R 1 is greater than R 2
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Unformatted text preview: (b) When the bulbs are connected in series the current in them is the same. The power dissipated by bulb 1 is now P 1 = i 2 R 1 and the power dissipated by bulb 2 is P 2 = i 2 R 2 . Since R 1 is greater than R 2 greater power is dissipated by bulb 1 than by bulb 2 and bulb 1 is the brighter of the two....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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