P28_027 - note that the current is the same in every...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
27. Let the resistors be divided into groups of n resistors each, with all the resistors in the same group connected in series. Suppose there are m such groups that are connected in parallel with each other. Let R be the resistance of any one of the resistors. Then the equivalent resistance of any group is nR , and R eq , the equivalent resistance of the whole array, satisFes 1 R eq = m X 1 1 nR = m nR . Since the problem requires R eq = 10 Ω = R , we must select n = m . Next we make use of Eq. 28-13. We
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: note that the current is the same in every resistor and there are n m = n 2 resistors, so the maximum total power that can be dissipated is P total = n 2 P , where P = 1 . 0 W is the maximum power that can be dissipated by any one of the resistors. The problem demands P total 5 . P , so n 2 must be at least as large as 5 . 0. Since n must be an integer, the smallest it can be is 3. The least number of resistors is n 2 = 9....
View Full Document

Ask a homework question - tutors are online