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Unformatted text preview: ( b 2 a 2 ) C + a 2 A = (0 . 380 10 3 m) 2 (0 . 250 10 3 m) 2 (1 . 69 10 8 m) +(0 . 250 10 3 m) 2 (2 . 75 10 8 m) = 3 . 10 10 15 m 3 . Thus, i C = (0 . 250 10 3 m) 2 (2 . 75 10 8 m)(2 . 00 A) 3 . 10 10 15 m 3 = 1 . 11 A and i A = (0 . 380 10 3 m) 2 (0 . 250 10 3 m) 2 (1 . 69 10 8 m)(2 . 00 A) 3 . 10 10 15 m 3 = . 893 A . (b) Consider the copper wire. IF V is the potential diference, then the current is given by V = i C R C = i C C L/a 2 , so L = a 2 V i C C = ( )(0 . 250 10 3 m) 2 (12 . 0 V) (1 . 11 A)(1 . 69 10 8 m) = 126 m ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics, Current, Resistance, Heat

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