P28_037 - 37. (a) The current in R1 is given by i1 = E 5.0...

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37. (a) The current in R 1 is given by i 1 = E R 1 + R 2 R 3 / ( R 2 + R 3 ) = 5 . 0V 2 . 0Ω+(4 . 0 Ω)(6 . 0Ω) / (4 . 0Ω+6 . 0Ω) =1 . 14 A . Thus i 3 = E− V 1 R 3 = E− i 1 R 1 R 3 = 5 . 0V (1 . 14 A)(2 . 0Ω) 6 . 0Ω =0 . 45 A . (b) We simply interchange subscripts 1 and 3 in the equation above. Now i 3 = E R 3 +( R 2 R 1 / ( R 2 + R
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