P28_038 - 38. (a) E = V + ir = 12 V + (10 A)(0.050 ) = 12.5...

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38. (a) E = V + ir = 12 V + (10 A)(0 . 050 Ω) = 12 . 5V. (b) Now E = V 0 +( i motor +8 . 0A) r ,where V 0 = i 0 A R light =(8 . 0A)(12V / 10 A) = 9 . 6 V. Therefore,
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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