P28_050 - 1 2 C E 2 is the energy stored in the capacitor....

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50. (a) The charge q on the capacitor as a function of time is q ( t )=( E C )(1 e t/RC ), so the charging current is i ( t )= dq/dt =( E /R ) e t/RC . The energy supplied by the emf is then U = Z 0 E idt = E 2 R Z 0 e t/RC dt = C E 2 =2 U C where U C =
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Unformatted text preview: 1 2 C E 2 is the energy stored in the capacitor. (b) By directly integrating i 2 R we obtain U R = Z i 2 Rdt = E 2 R Z e 2 t/RC dt = 1 2 C E 2 ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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