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Unformatted text preview: ) e t/ into V R = iR to obtain V R = q R e t/ = (1 . 10 3 C)(1 . 10 6 ) 1 . 0 s e t/ 1 . 0 s = (1 . 10 3 V) e 1 . t , where t is measured in seconds. (d) We substitute i = ( q / ) e t/ into P = i 2 R to obtain P = q 2 R 2 e 2 t/ = (1 . 10 3 C) 2 (1 . 10 6 ) (1 . 0 s) 2 e 2 t/ 1 . 0 s = (1 . 0 W) e 2 . t , where t is again measured in seconds....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics, Capacitance, Charge, Energy

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