P28_056 - i through the two feet(each represented by R f =...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
56. (a) We found in part (e) of problem 45 in Chapter 27 that the magnitude of the electric Feld is E = 16 V/m. Taking this to be roughly constant over the small distance ( ` =0 . 50 m) involved here, then we approximate the potential di±erence between the man’s feet as V E` =8V . (b) The voltage found in part (a) drives a current
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: i through the two feet (each represented by R f = 300 Ω) and the torso (represented by R t = 1000 Ω). Thus, i = ∆ V 2 R f + R t = 8 V 2(300 Ω) + 1000 Ω which yields i ≈ 5 mA. (c) Our value for i is far less than the stated 100 mA minimum required to put the heart into Fbrillation....
View Full Document

This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

Ask a homework question - tutors are online