Unformatted text preview: i through the two feet (each represented by R f = 300 Ω) and the torso (represented by R t = 1000 Ω). Thus, i = ∆ V 2 R f + R t = 8 V 2(300 Ω) + 1000 Ω which yields i ≈ 5 mA. (c) Our value for i is far less than the stated 100 mA minimum required to put the heart into Fbrillation....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
- Fall '08