60.(a) The magnitude of the current density vector isJA=JB=iA=V(R1+R2)A=4V(R1+R2)πD2=4(60.0V)π(0.127 Ω + 0.729 Ω)(2.60×10−3m)2=1.32×107A/m2.(b)VA=VR1/(R1+R2)=(60.0 V)(0.127 Ω)/(0.127 Ω + 0.729 Ω) = 8.90V, andVB=V−VA=60.0V−8.9V=51.1V.(c) Calculate the resistivity fromR=ρL/Afor both materials:ρA=RAA/L
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.