P28_069 - 69 The voltage across the rightmost resistors is...

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69. The voltage across the rightmost resistors is V 12 =(1 . 4 A)(8 . 0Ω+4 . 0Ω )=16 . 8 V, which is equal to V 16 (the voltage across the 16 Ω resistor, which has current equal to V 16 / (16 Ω) = 1 . 05 A). By the junction rule, the current in the rightmost 2 . 0 Ω resistor is 1 . 05 + 1 . 4=2 . 45 A, so its voltage is V 2 =(2 . 0 Ω)(2 . 45 A) = 4 . 9 V. The loop rule tells us the voltage across the 2 . 0 Ω resistor (the one
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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