P28_071 - . 0 . Thus, i 1 = 1 2 i bat = 1 2 12 V 6 . 0 = 1...

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71. (a) By symmetry, we see that i 1 is half the current that goes through the battery. The battery current is found by dividing E by the equivalent resistance of the circuit, which is easily found to be 6
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Unformatted text preview: . 0 . Thus, i 1 = 1 2 i bat = 1 2 12 V 6 . 0 = 1 . 0 A and is clearly downward (in the Fgure). (b) We use Eq. 28-14: P = i bat E = 24 W....
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