P28_073 - 73(a We reduce the parallel pair of identical 2.0...

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73. (a) We reduce the parallel pair of identical 2 . 0 Ω resistors (on the right side) to R 0 =1 . 0Ω ,andwe reduce the series pair of identical 2 . 0 Ω resistors (on the upper left side) to R 0 =4 . 0Ω . W ith R denoting the 2 . 0 Ω resistor at the bottom (between V 2 and V 1 ), we now have three resistors in series which are equivalent to R + R 0 + R 0 =7 . 0Ω across which the voltage is 7.0 V (by the loop rule, this is 12 V 5 . 0 V), implying that the current is 1.0 A (clockwise). Thus, the voltage across R 0 is (1 . 0 A)(1 . 0Ω
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