P28_082 - P R = 100 R ( E x/R ) 2 (100 R/R + 10 x x 2 ) 2...

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82. The part of R 0 connected in parallel with R is given by R 1 = R 0 x/L ,where L = 10 cm. The voltage diFerence across R is then V R = E R 0 /R eq ,whe re R 0 = RR 1 / ( R + R 1 ) and R eq = R 0 (1 x/L )+ R 0 . Thus P R = V 2 R R = 1 R µ E RR 1 / ( R + R 1 ) R 0 (1 x/L )+ RR 1 / ( R + R 1 ) 2 .
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Unformatted text preview: P R = 100 R ( E x/R ) 2 (100 R/R + 10 x x 2 ) 2 where x is measured in cm....
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