P28_083 - (b) For P = 100 W, R eq = R 1 = E 2 /P = (120 V)...

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83. (a) Since P = E 2 /R eq , the higher the power rating the smaller the value of R eq . To achieve this, we can let the low position connect to the larger resistance ( R 1 ), middle position connect to the smaller resistance ( R 2 ), and the high position connect to both of them in parallel.
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Unformatted text preview: (b) For P = 100 W, R eq = R 1 = E 2 /P = (120 V) 2 / 100 W = 144 ; for P = 300 W, R eq = R 1 R 2 / ( R 1 + R 2 ) = (144 ) R 2 / (144 + R 2 ) = (120 V) 2 / 300 W . We obtain R 2 = 72 ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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