P28_088 - more like a series pair(having the same current...

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88. (a) The capacitoris initially uncharged, which implies (by the loop rule) that there is zero voltage (at t = 0) across the 10 kΩ resistor, and that 30 V is across the 20 kΩ resistor. Therefore, by Ohm’s law, i 10 =0, (b) and i 20 =(30V) / (20 kΩ) = 1 . 5 × 10 3 A. (c) As t →∞ the current to the capacitor reduces to zero and the 20 kΩ and 10 kΩ resistors behave
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Unformatted text preview: more like a series pair (having the same current), equivalent to 30 kΩ. The current through them, then, at long times, is i = (30 V) / (30 kΩ) = 1 . × 10 − 3 A....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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