P28_095 - i 1 = i 2 + i 3 = 0 . 0382 A (downward). (b) See...

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95. (Third problem of Cluster ) (a) Using the junction rule ( i 1 = i 2 + i 3 )wewr itetwoloopru leequat ions : E 1 i 2 R 2 ( i 2 + i 3 ) R 1 =0 E 2 i 3 R 3 ( i 2 + i 3 ) R 1 =0 . Solving, we Fnd i 2 =0 . 0109 A (rightward, as was assumed in writing the equations as we did), i 3 =0
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Unformatted text preview: i 1 = i 2 + i 3 = 0 . 0382 A (downward). (b) See the results in part (a). (c) See the results in part (a). (d) The voltage across R 1 equals V A : (0 . 0382 A)(100 ) = +3 . 82 V....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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