96. (Fourth problem ofCluster)(a) The symmetry of the problem allows us to usei2as the current inbothof theR2resistors andi1fortheR1resistors. We see from the junction rule thati3=i1−i2. There are only two independentloop rule equations:E−i2R2−i1R1=02i1R1−(i1−i2)R3.where in the latter equation, a zigzag path through the bridge has been taken. Solving, we ±nd
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.