4.(a) The force on the electron is~FB=q~v×~B=q(vxˆi+vyˆj)×(BxˆBy~j)=q(vxBy−vyBx)ˆk=(−1.6×10−19C)[(2.0×106m/s)(−0.15 T)−(3.0×106m/s)(0.030 T)]6.2×10−14N)ˆk.Thus, the magnitude of~FBis 6.2×1014N, and~FBpoints in the positivezdirection.(b) This amounts to repeating the above computation with a change in the sign in the charge. Thus,
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.