P29_006 - i] = (6 . 4 10 19 N) i + (8 . 10 19 N) k . The...

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6. (a) The net force on the proton is given by ~ F = ~ F E + ~ F B = q ~ E + q~v × ~ B =( 1 . 6 × 10 19 C)[(4 . 0V / m) ˆ k + (2000 m / s) ˆ j × ( 2 . 5mT) ˆ i] =( 1 . 4 × 10 18 N) ˆ k . (b) In this case ~ F = ~ F E + ~ F B = q ~ E + q~v × ~ B =( 1 . 6 × 10 19 C)[( 4 . 0V / m) ˆ k + (2000 m / s) ˆ j × ( 2 . 5mT) ˆ i] =( 1 . 6 × 10 19 N) ˆ k . (c) In the Fnal case, ~ F = ~ F E + ~ F B = q ~ E + q~v × ~ B =( 1 . 6 × 10 19 C)[(4 . 0V / m) ˆ i + (2000 m / s) ˆ j × ( 2 . 5mT) ˆ
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Unformatted text preview: i] = (6 . 4 10 19 N) i + (8 . 10 19 N) k . The magnitude of the force is now q F 2 x + F 2 y + F 2 z = p (6 . 4 10 19 N) 2 + 0 + (8 . 10 19 N) 2 = 1 . 10 18 N ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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