P29_017 - 17. (a) From K = 1 me v 2 we get 2 v= 2K = me...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
17. (a) From K = 1 2 m e v 2 we get v = r 2 K m e = s 2(1 . 20 × 10 3 eV)(1 . 60 × 10 19 eV / J) 9 . 11 × 10 31 kg =2 . 05 × 10 7 m / s . (b) From r = m e v/qB we get B = m e v qr = (9 . 11 × 10 31 kg)(2 . 05 × 10 7 m / s) (1 . 60 × 10 19 C)(25 . 0 × 10 2 m) =4 . 67 × 10 4 T . (c) The “orbital” frequency is f = v 2 πr = 2 . 07
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

Ask a homework question - tutors are online