P29_020 - 20(a Using Eq 29-16 we obtain v= rqB 2eB 2(4.50 102 m(1.60 1019 C(1.20 T = = = 2.60 106 m/s m 4.00 u(4.00 u(1.66 1027 kg/u(b T = 2r/v =

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20. (a) Using Eq. 29-16, we obtain v = rqB m α = 2 eB 4 . 00 u = 2(4 . 50 × 10 2 m)(1 . 60 × 10 19 C)(1 . 20 T) (4 . 00 u)(1 . 66 × 10 27 kg / u) =2 . 60 × 10 6 m / s . (b) T =2 πr/v =2 π (4 . 50 × 10 2 m) / (2 . 60 × 10 6 m / s) = 1 . 09 × 10 7 s. (c) The kinetic energy of the alpha particle is K = 1 2 m α v 2 = (4 . 00 u)(1
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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