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20.
(a) Using Eq. 2916, we obtain
v
=
rqB
m
α
=
2
eB
4
.
00 u
=
2(4
.
50
×
10
−
2
m)(1
.
60
×
10
−
19
C)(1
.
20 T)
(4
.
00 u)(1
.
66
×
10
−
27
kg
/
u)
=2
.
60
×
10
6
m
/
s
.
(b)
T
=2
πr/v
=2
π
(4
.
50
×
10
−
2
m)
/
(2
.
60
×
10
6
m
/
s) = 1
.
09
×
10
−
7
s.
(c) The kinetic energy of the alpha particle is
K
=
1
2
m
α
v
2
=
(4
.
00 u)(1
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics, Energy, Kinetic Energy

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