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Unformatted text preview: 8 kg / s) 3 . 92 10 25 kg = 2 . 27 10 2 A . (c) Each ion deposits energy qV in the cup, so the energy deposited in time t is given by E = NqV t = iqV q t = iV t . For t = 1 . 0h, E = (2 . 27 10 2 A)(100 10 3 V)(3600 s) = 8 . 17 10 6 J . To obtain the second expression, i/q is substituted for N ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics

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