26. The equation of motion for the proton is~F=q~v×~B=q(vxˆi+vyˆj+vzˆk)×Bˆi=qB(vzˆj−vyˆk)=mp~a=mp·µdvxdt¶ˆµdvydt¶ˆµdvzdt¶ˆk¸.Thus,dvxdt=0dvydt=ωvzdvzdt=−y,whereω=eB/mp. The solution isvx=v0x,vy=v0ycosωtandvz=
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.