26. The equation of motion for the proton is
~
F
=
q~v
×
~
B
=
q
(
v
x
ˆ
i+
v
y
ˆ
j+
v
z
ˆ
k)
×
B
ˆ
i=
qB
(
v
z
ˆ
j
−
v
y
ˆ
k)
=
m
p
~a
=
m
p
·µ
dv
x
dt
¶
ˆ
µ
dv
y
dt
¶
ˆ
µ
dv
z
dt
¶
ˆ
k
¸
.
Thus,
dv
x
dt
=0
dv
y
dt
=
ωv
z
dv
z
dt
=
−
y
,
where
ω
=
eB/m
p
. The solution is
v
x
=
v
0
x
,
v
y
=
v
0
y
cos
ωt
and
v
z
=
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics

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